Lesson Plan
Period #4 Velocity Review / Intro To Acceleration
Materials : Textbook : Physics - Principles and Problems
Velocity Fun Sheet
Lab #3 - Measuring Acceleration
Review : Go over Questions 13-18 on pages 55 of textbook
Practice finding average and instantaneous velocity, find displacement using a velocity vs time graph, and review terms and definitions, practice calculations using velocity formula
Objectives : students should be able to :
Kinematics
(Acceleration in One Dimension)It is expected that students will demonstrate an understanding of the relationships between time, velocity, displacement, and acceleration and apply these relationships to calculations in common situations.
- define acceleration
- use velocity-versus-time graphs to determine the instantaneous or average acceleration of objects
- solve problems for objects with constant acceleration, involving: displacement , initial velocity, final velocity, acceleration, time
Part I - Acceleration - Introduction and Notes :
Give Notes starting at "ACCELERATION" p. 2-23, define acceleration, and introduce the formula for acceleration.
Do examples on pages 2-23 and 2-24
Do Lab #3 - Measuring Acceleration
Guided Study :
"Check your understanding" page 2 -25, find acceleration in both cases.
Exercise :
Questions 1-4 page 66 Practice Problems in Textbook
Questions 9 - 12 page 69 Practice Problems in Textbook
Evaluation :
Lab #3 - Measuring Acceleration
Questions 1-4 page 66 Practice Problems in Textbook
Acceleration Quiz
Unit Two Test
Displacement During Acceleration
Practice Questions :
- A skier accelerates from rest at 1.20 m/s2 down an icy slope. How far does she get in a) 5.0 s? b) 10.0 s c) 15.0 s?
- What is the acceleration of an object that accelerates steadily from rest, traveling 2.0 m/s in 2.0 s?
- How long does it take an airplane accelerating from rest at 5.0 m/s2 to travel 360 m?
Ans.
2-26
- 15 m, 60.0 m, 135 m
- 1.0 m/s
- 12 s
- Displacement and Acceleration :
We can calculate the displacement of an object that has CONSTANT acceleration.
We know that
vave = vf + vi
2
so since
d = vave t = (vf + vi) t
2
We also know that :
aave = vf - vi
t
we can solve this equation for vf
vf = at + vi
and substitue this equation into our first equation
d = (at + vi + vi) t = (2vi + at) t = vit + ½ at2
2 2
d = vit + ½ at2
** remember, this equation holds true ONLY at constant acceleration
note what happens when velocity is constant (ie. a = 0)
d = vit + ½ at2
zero
and out equation becomes
d = vt (since if v is constant vi = vf = vave)
In the SPECIAL CASE of Acceleration From Rest vi = 0
and the equation becomes :
d = vit + ½ at2 = ½ at2
zero
Example
A. How far down a smooth ramp does a 5.0 kg cart roll in 8.0 seconds accelerating from rest at 2.5 m/s?
d = ½ at2 = ½ (2.5 m/s)(8.0 s)2 = 8.0 x 101 m
B. How far will it roll if its initial velocity was 2.0 m/s?
d = vit + ½ at2 = (2.0 m/s)(8.0s) + ½ (2.5 m/s)(8.0 s)2
= 96 m